x^2+2x-15 (all over) x-3 equals 3.
(x-3) * x^2+2x-15 (all over) x-3 equals 3 *(x-3)
x^2+2x-15=3x-9
x^2-x-6=0
(x-3)(x+2)=0
x-3=0 or x+2=0
x={3, -2}
I did something wrong here but I'm not sure what I did that is wrong. What is my error? Or is it the solution?
Nothing wrong in your steps,
except at the end when you have
x = 3 or x = -2, we can't allow x = 3, since we then would have divided the original by zero, which we can't do
so the only answer is x = -2
Had you factored like in the previous ....
(x+5)(x-3)/(x-3) = 3
x+5 = 3
x = -2