calculate the volume of air required for complete combustion of 1m^3 of gaseous fuel having the combustion:CO=46%,CH4=10%,H2=4%,C2H2=2.0%,N2=1% and the remaining being CO2
To calculate the volume of air required for complete combustion of the gaseous fuel, we need to determine the stoichiometric ratio of fuel-to-air, i.e., the ratio in which the fuel and air need to be mixed to ensure complete combustion.
The stoichiometric ratio can be determined by converting the fuel composition to the molar ratio of each component. The molar ratios can then be used to calculate the overall stoichiometric ratio.
Given the combustion composition:
CO = 46%
CH4 = 10%
H2 = 4%
C2H2 = 2.0%
N2 = 1%
CO2 = remaining
First, we need to determine the molar ratios for each component.
1. Convert the percentages to decimal form:
CO = 46% = 0.46
CH4 = 10% = 0.10
H2 = 4% = 0.04
C2H2 = 2.0% = 0.02
N2 = 1% = 0.01
2. Calculate the moles of each component using the volume of 1m^3:
Since the volume is 1m^3, the moles of each component will be equal to their respective percentages in molar form (using 22.4 L/mol as the volume of 1 mole of gas at standard temperature and pressure):
Moles of CO = 0.46 x 1 mol = 0.46 mol
Moles of CH4 = 0.10 x 1 mol = 0.10 mol
Moles of H2 = 0.04 x 1 mol = 0.04 mol
Moles of C2H2 = 0.02 x 1 mol = 0.02 mol
Moles of N2 = 0.01 x 1 mol = 0.01 mol
3. Determine the stoichiometric ratio based on the moles of each component:
The stoichiometry of complete combustion can be expressed as:
Fuel + (a x O2 + b x N2) -> c x CO2 + d x H2O + e x N2
where a, b, c, d, and e are the coefficients representing the molar ratios of each component.
Assuming complete combustion, the balanced equation will be:
1 CO + 2 CH4 + 4 H2 + 2 C2H2 + 0.79 N2 -> c x CO2 + d x H2O + e x N2
Now, calculate the moles of CO2 produced based on the moles of fuel:
Moles of CO2 = 0.46 x c mol
Moles of H2O = 0.10 x 2 mol + 0.04 x 4 mol + 0.02 x 2 mol
Moles of N2 = 0.79 x c mol
Since we have the composition of the combustion products, we can also calculate the moles of CO2 using the remaining percentages:
Moles of CO2 = (100% - (46% + 10% + 4% + 2.0% + 1%)) x 1 mol
Now, we can equate the moles of CO2 produced based on the fuel composition and based on the remaining percentages, and solve for c:
0.46 x c = (100% - (46% + 10% + 4% + 2.0% + 1%)) x 1 mol
Solving the equation will give us the value of c, which represents the stoichiometric ratio for CO2. The value of c is the molar ratio of CO2 produced per mole of fuel.
Finally, the volume of air required can be calculated by multiplying the moles of air required by the molar volume of air at standard temperature and pressure (22.4 L/mol).
Please note that without the values for c, d, and e, it is not possible to accurately calculate the volume of air required for complete combustion.