Math

posted by Sasha

How many real number solutions does the equation have? y=3x^2-5x-5

A)one solution
B)two solutions
C)no solutions
D)infinitely many solutions

I can't figure this question out. Any help would be amazing.

  1. Reiny

    make a sketch of the graph using
    x = -1,0,1,2,3

  2. Sasha

    I still don't get it... Should I graph them as points? Because when I graph just x=-1 and ect... I get straight lines going up and down at the following points, (-1,0), (0,0),(1,0),(2,0),(3,0).

  3. Sasha

    Is it no solutions?

  4. Sasha

    No, the answer is two solutions, Correct?

  5. Reiny

    your first response tells me you are having difficulties evaluating a function for a given x

    x = -1 , y = 3(-1)^2 - 5(-1) - 5 = 3+5-5 = 3
    so the point is (-1,3)
    x = 0 , y = -5 , so the point is (0,-5)
    x = 1 , y = 3(1)^2 -5(1) - 5 = -7
    so the point is (1,-7)
    x = 2 , y = -3 , point is (2,-3)
    x = 3, y = 7 , point (3,7)

    without even looking at the graph and knowing that it is a parabola opening upwards, I can see that the graph from (-1,3) to (0,-5) must have crossed the x-axis, and from (2,-3) to (3,7) must have crossed it a second time,
    so, yes, there are two solutions.

    Looks like you are just guessing.

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