Chemistry

posted by Bob

A 50 ml sample of .150M Ch3CooH is titrations with .150 M NaOh solution. Calculate the ph after the following volumes of base have been added: 49 ml, 51ml

  1. DrBob222

    CH3COOH + NaOH --> CH3COONa + H2O
    millimols CH3COOH = 50 x 0.150 = ?
    millimols NaOH = 49 x 0.150 = ?
    mmols CH3COOH left = the difference.
    M CH3COOH = mmols/total mL = ?
    Then convert to pH.

  2. didi

    for 49 ml: pH=2.8
    for 51 ml: pH=11.17

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