A stationary pool ball with mass 0.20 kg is struck with an average force of 35 N over a time of 18 ms. What speed does it have just after impact?
a = F/M = 35/0.2 = 175 m/s^2
V = Vo + a*t = 0 + 175 * 0.018 = 3.15 m/s
To find the speed of the pool ball just after impact, we can use the impulse-momentum principle. The impulse can be calculated by multiplying the average force (F) by the time (t):
Impulse (J) = F * t
Given:
Mass of the pool ball (m) = 0.20 kg
Average force (F) = 35 N
Time (t) = 18 ms = 18 * 10^-3 seconds
J = F * t
J = 35 N * 18 * 10^-3 s
J ≈ 0.63 kg·m/s
Next, we can use the formula for impulse-momentum to find the final velocity (v) of the ball:
J = m * v
Substituting the known values:
0.63 kg·m/s = 0.20 kg * v
Rearranging the equation to solve for v:
v = J / m
v = 0.63 kg·m/s / 0.20 kg
The speed of the pool ball just after impact is approximately:
v ≈ 3.15 m/s
To find the speed of the pool ball just after impact, we can use the equation:
v = (F * t) / m
where:
v is the final velocity (speed) of the pool ball
F is the force applied to the pool ball
t is the time over which the force is applied
m is the mass of the pool ball
Given:
F = 35 N
t = 18 ms = 18 * 10^(-3) s
m = 0.20 kg
Plugging in the values, we get:
v = (35 * 18 * 10^(-3)) / 0.20
v = 6.3 m/s
Therefore, the pool ball has a speed of 6.3 m/s just after impact.