How would i do a table of values for this equation: y=1/2(3)^-2x starting from -5 to 5
i get these values: -0.2778, -0.2222, -0.1667, -0.1111, -0.0556, 0 etc... ami wrong?
To create a table of values for the equation y = (1/2) * (3)^(-2x), you can substitute different values of x into the equation and calculate the corresponding values of y.
Let's start with the given range of x values from -5 to 5.
Step 1: Substitute each value of x into the equation and simplify.
- Substituting x = -5:
y = (1/2) * (3)^(-2 * (-5))
= (1/2) * (3)^(10)
≈ 40.5
- Substituting x = -4:
y = (1/2) * (3)^(-2 * (-4))
= (1/2) * (3)^(8)
≈ 10.1
By continuing this process for each value of x in the given range, you can complete the table:
x | y
------------
-5 | 40.5
-4 | 10.1
-3 | 2.5
-2 | 0.6
-1 | 0.1
0 | 0.02
1 | 0.004
2 | 0.001
3 | 0.0002
4 | 0.00003
5 | 0.000006
Comparing these values to the ones you mentioned (-0.2778, -0.2222, -0.1667, -0.1111, -0.0556, 0), it seems that some calculations made by you might be incorrect. Double-check your calculations or utilize a calculator to ensure the accuracy of your results.