How many milliliters of a 5.0 M H2SO4 stock solution would you need to prepare 111.0 mL of 0.36 M H2SO4?

To determine how many milliliters of a 5.0 M H2SO4 stock solution you would need to prepare 111.0 mL of 0.36 M H2SO4, we can use the formula:

C1V1 = C2V2

Where:
C1 = initial concentration (M) of the stock solution
V1 = volume (mL) of the stock solution
C2 = final concentration (M) of the diluted solution
V2 = final volume (mL) of the diluted solution

In this case, we are given:
C1 = 5.0 M
C2 = 0.36 M
V2 = 111.0 mL

Rearranging the formula to solve for V1, we have:
V1 = (C2 * V2) / C1

Substituting the given values, we get:
V1 = (0.36 M * 111.0 mL) / 5.0 M

Now we can calculate:
V1 = (39.96 mL) / 5.0
V1 = 7.992 mL

Therefore, you would need to measure out approximately 7.992 milliliters of the 5.0 M H2SO4 stock solution to prepare 111.0 mL of 0.36 M H2SO4.

mL1 x M1 = mL2 x M2