At a constant velocity, a 5kg bag of cement is pulled straight up a 7m wall. How much work is done by the puller? (Gravitational pull is 9.8m/s2, W(J)=F(N)*D(m)

How do I work this problem??

work = force * distance (w= f * d)

w= (7*9.8)5
343j
since work is measured in joule (J)

5 * 9.81 * 7 Joules

343 j

thank u for your solution

How do you solve this. At a constant velocity, a 5kg bag of cement is pulled straight up a 7m wall. How much work is done by the puller? (Gravitational pull is 9.8m/s2, W(J)=F(N)*D(m). I need to see the work done to get the answer.

To determine the amount of work done by the puller, we need to calculate the force exerted and the distance over which the force is applied.

First, let's calculate the force exerted by the puller. Since the bag is being pulled straight up, the force required is equal to the weight of the bag. The weight can be calculated using the formula W = m * g, where W is the weight, m is the mass, and g is the acceleration due to gravity.

Given that the mass of the bag is 5kg and the acceleration due to gravity is 9.8m/s², we can substitute these values into the formula to find the weight:

W = 5kg * 9.8m/s² = 49N

So, the force exerted by the puller is 49 Newtons (N).

Now, we need to calculate the distance over which the force is applied. It is given in the problem that the bag is pulled up a 7-meter wall, so the distance over which the force is applied is 7 meters.

Using the formula for work, W = F * d, where W is the work, F is the force, and d is the distance, we can substitute the values:

W = 49N * 7m = 343 Joules (J)

Therefore, the work done by the puller is 343 Joules.