1. what would happen to the the cell potential in a voltaic cell if the salt bridge lost contact with one of the solutions?

2. would a reaction occur if solid tin was placed in a solution of copper II nitrate? If so, write the balanced net ionic equation for the reaction.

1. The cell potential would drop to zero since the circuit has been broken.

2. Yes, Sn will displace Cu^2+.
Sn(s) + Cu^2+ ==> Sn(2^+) + Cu(s)

Here is the activity series.
https://www.google.com/search?q=activity+series&tbm=isch&imgil=COkl6kSFzOOkZM%253A%253BO97ZY4ZQ8eeUCM%253Bhttp%25253A%25252F%25252Farchives.jesuitnola.org%25252Fupload%25252Fclark%25252FRefs%25252Fsolu_act.htm&source=iu&pf=m&fir=COkl6kSFzOOkZM%253A%252CO97ZY4ZQ8eeUCM%252C_&usg=__sGCXOYhWi1CGYCv55IB5bG69IkQ%3D&biw=1024&bih=609&dpr=1.25&ved=0CDQQyjc&ei=NZFbVfuON4uWNtTKgegI#imgrc=COkl6kSFzOOkZM%253A%3BO97ZY4ZQ8eeUCM%3Bhttp%253A%252F%252Farchives.jesuitnola.org%252Fupload%252Fclark%252FRefs%252Fact_series.gif%3Bhttp%253A%252F%252Farchives.jesuitnola.org%252Fupload%252Fclark%252FRefs%252Fsolu_act.htm%3B398%3B399

These are single replacement reactions. Any METAL will displace the ION of a metal below it in the activity series.
Note that Cu + Sn(NO3)2 ==> no reaction since Cu is BELOW Sn.

thank you

1. If the salt bridge lost contact with one of the solutions in a voltaic cell, it would disrupt the flow of ions between the two half-cells. The salt bridge acts as a medium to balance the charges in the solutions, allowing ions from the salt bridge to migrate and maintain electrical neutrality. Without this connection, charge buildup would occur in one of the half-cells, causing a disruption in the cell potential. Eventually, the flow of electrons would stop, and the cell would no longer produce an electric current.

2. Yes, a reaction would occur if solid tin (Sn) was placed in a solution of copper II nitrate (Cu(NO3)2). The balanced net ionic equation for this reaction can be found by breaking down the compounds and identifying the ions involved:

Cu(NO3)2 (aq) + Sn (s) -> Cu (s) + Sn(NO3)2 (aq)

To find the net ionic equation, we need to determine which ions participate in the reaction. In this case, it would be the copper ion (Cu²⁺) and the tin ion (Sn²⁺). The nitrate ion (NO3⁻) remains a spectator ion and does not directly participate in the reaction. Therefore, the balanced net ionic equation is:

Cu²⁺ (aq) + Sn (s) -> Cu (s) + Sn²⁺ (aq)