if 6.5kJ of energy are added to 56.4g sample of iron at 24 degrees C what is the final temperature of the iron? The specific heat of iron is 0.449j/gC
q = mass Fe x specific heat Fe x (Tfinal-Tinitial)
Substitute and solve for Tfinal
To find the final temperature of the iron, we can use the equation:
q = m * c * ΔT
Where:
q = energy added (in Joules)
m = mass of the sample (in grams)
c = specific heat of iron (in J/g°C)
ΔT = change in temperature (in °C)
First, let's convert the energy added from kilojoules to joules:
6.5 kJ = 6.5 * 1000 J = 6500 J
Now, we can rearrange the equation to solve for ΔT:
ΔT = q / (m * c)
Substituting the given values:
ΔT = 6500 J / (56.4 g * 0.449 J/g°C)
Now, we can calculate the final temperature:
Final temperature = Initial temperature + ΔT
Given that the initial temperature is 24°C, we can substitute the values and solve for the final temperature.