i can't figure this out if someone could please help me that would be great.
x3 " 3y for x = 4, y = -4 is it 0 ?
3*4=12 and 3*-4=-12= 0
To solve the expression x^3 - 3y for x = 4 and y = -4, you need to substitute these values into the equation. Here's how you can do it step-by-step:
Step 1: Write down the expression: x^3 - 3y
Step 2: Replace x with 4 and y with -4 in the expression: (4)^3 - 3(-4)
Step 3: Evaluate the expression using the given values:
(4)^3 = 4 × 4 × 4 = 64
-3(-4) = 12 (since negative multiplied by negative gives a positive)
Step 4: Simplify the expression further:
64 - 12 = 52
Therefore, the value of the expression x^3 - 3y, when x = 4 and y = -4, is 52, not 0.