A cable is 32 feet 10 1/2 inches long is to be cut into 8 1/2 inches lengths. Allow 1/16 inch for each saw cut.
What is your question?
How do you account for the 1/16 inch cuts?
The saw is probably about 1/16-inch-thick -- therefore you'll have some waste.
Would you add the 1/16 inch to the 8 1/2 inch to account for each cut and then divide by the 32 FT 10 1/2 inch? or what? I'm confused on how to go about doing the problem.
What is the question you're trying to solve?
To find out how many 8 1/2 inch lengths can be cut from a 32 feet 10 1/2 inch cable, we will first convert the cable length to inches.
Since there are 12 inches in a foot, the cable length can be calculated as follows:
32 feet * 12 inches/foot = 384 inches
10 1/2 inches = 10.5 inches
Therefore, the total cable length in inches is:
384 inches + 10.5 inches = 394.5 inches
Next, we need to subtract the amount of extra length needed for saw cuts. Given that we need to allow 1/16 inch for each saw cut, and we have 8 1/2 inch lengths, the total extra length needed is:
8 1/2 inches * (1/16 inch/saw cut) = 8.5 inches * (1/16) = 0.53125 inches
Now we can subtract the extra length from the total cable length:
394.5 inches - 0.53125 inches = 394.96875 inches
To find out how many 8 1/2 inch lengths can be cut from this cable, we divide the total cable length by the length of each cut:
394.96875 inches / 8 1/2 inches = 46.46579...
Since we can't have a fraction of a length, we round down to the nearest whole number. Therefore, you can cut 46 lengths of 8 1/2 inches from the cable.