Two identical 2 ohm resistors are connected in parallel to a 1 ohm resistor in the circuit.the potential difference across the cell is 6 v and internal resistance is negligible.calculate the effect across the parallel combination
three resistors in parallel? Exactly what are you looking for?
To calculate the effective resistance across the parallel combination of two 2 ohm resistors connected in parallel with a 1 ohm resistor, you can use the formula:
1 / Reff = 1 / R1 + 1 / R2
Where Reff is the effective resistance and R1, R2 are the individual resistances.
In this case, R1 = R2 = 2 ohms, and R3 (the 1 ohm resistor) is connected in series with the parallel combination. The total resistance in the circuit can be calculated by adding R3 to Reff.
1 / Reff = 1 / R1 + 1 / R2
1 / Reff = 1 / 2 + 1 / 2
1 / Reff = 1 + 1 / 2
1 / Reff = 2 / 2 + 1 / 2
1 / Reff = 3 / 2
Now, we can find the effective resistance Reff by taking the reciprocal of both sides of the equation:
Reff = 2 / 3 ohms
Since the internal resistance is negligible, the total resistance in the circuit is simply the sum of Rs and Reff:
Total Resistance = R3 + Reff
Total Resistance = 1 + 2 / 3
Total Resistance = 3 / 3 + 2 / 3
Total Resistance = 5 / 3 ohms
To calculate the potential difference across the parallel combination, you can use Ohm's Law:
V = I * R
where V is the potential difference, I is the current, and R is the resistance.
In this case, the potential difference across the cell is given as 6V. Since the internal resistance is negligible, the potential difference across the parallel combination is equal to the potential difference across the cell.
Therefore, the potential difference across the parallel combination is 6V.