What is the area of an isosceles right triangle wih equal sides that measure 42cm? @Ms. Sue please help!!!
A = bh/2
A = (45 * 45)/2
A = 1012.5 sq. cm.
thank you but can you help me with this question?
The area of a trapezoid with a height of 24m and bases of 6m and 8m.
So, I do 8+6=14
24 x 14=336
336 x 0.5 = 168 m^2
is my answer right?
Yes. You are right.
Ok i have two more questions i am completely confused with do you think you can help?
I'll try to help.
Please post these questions under New Questions.
To find the area of an isosceles right triangle, you can use the formula:
Area = (base * height) / 2
In this case, since it's an isosceles right triangle, the base and height will be the same. Let's call it "s".
Given that the equal sides of the triangle measure 42 cm, we know that the base and height are both 42 cm.
Now, substitute the values into the formula:
Area = (42 cm * 42 cm) / 2
To find the answer, you need to evaluate the expression:
Area = (1764 cm^2) / 2
Area = 882 cm^2
So the area of the isosceles right triangle with equal sides measuring 42 cm is 882 square centimeters.