In a bag M&M's, the probability of choosing a yellow m&m is 1/5. In a bag of skittles, the probability of choosing red is 1/4. What is the probability of choosing a yellow m&m and a red skittle??
Number of events:________________
Expression:________________
Answer:_______________
I know the expression which is 1/5*1/4 and I also know the answer, but I don't get the number of events part.
The number of events is 2, choosing the M&M and choosing the Skittle.
In a bag M&M's, the probability of choosing a yellow m&m is 1/5. In a bag of skittles, the probability of choosing red is 1/4. What is the probability of choosing a yellow m&m and a red skittle??
In this case, the "number of events" refers to the total number of possible outcomes or choices that can occur. To find the number of events, we need to know the total number of colors/flavors available for each candy.
Let's assume there are 6 different colors of M&M's and 5 different flavors of Skittles. Therefore, the number of events for choosing a yellow M&M would be 6, and the number of events for choosing a red Skittle would be 5.
So, the number of events for choosing a yellow M&M and a red Skittle would be the product of the number of events for each candy, which is 6 * 5 = 30.
Now, let's calculate the expression 1/5 * 1/4, which gives us the probability of choosing a yellow M&M and a red Skittle. Multiplying the probabilities, we get 1/20.
Therefore, the answer is:
Number of events: 30
Expression: 1/5 * 1/4
Answer: 1/20