Find the product of (2a + 3b)(2a − 3b).


A. 4a2 − 6b2
B. 2a2 − 3b2
C. 4a2 + 12ab − 9b2
D. 4a2 − 9b2

plz help

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To find the product of (2a + 3b)(2a − 3b), you can use the formula for multiplying binomials:

(a + b)(c + d) = ac + ad + bc + bd

In this case, the two binomials are (2a + 3b) and (2a − 3b). Applying the formula, we have:

(2a + 3b)(2a − 3b) = (2a)(2a) + (2a)(−3b) + (3b)(2a) + (3b)(−3b)

= 4a^2 − 6ab + 6ab − 9b^2

Simplifying this expression, we see that the two middle terms cancel out:

= 4a^2 − 9b^2

Therefore, the product of (2a + 3b)(2a − 3b) is 4a^2 − 9b^2.

So, the correct answer is option D. 4a^2 − 9b^2.

(2a + 3b)(2a − 3b)

Distribute each factor or use the FOIL method.
= (2a)(2a) + (2a)(-3b) + (3b)(2a) + (3b)(-3b)
= 4a^2 - 6ab + 6ab - 9b^2
= 4a^2 - 9b^2

ok thanks so much