Calculate the mass of Copper(II) Sulfate CuSo4 needed to make 3.00Lof 3.0 M solution?

How many mols do you want? That's mols = M x L = ?

Then mol = g/molar mass. You have mols and molar mass, solve for grams.

To calculate the mass of Copper(II) Sulfate (CuSO4) needed to make a 3.00 L solution with a concentration of 3.0 M, you need to follow these steps:

1. Determine the molar mass of CuSO4.
- The molar mass of Cu = 63.55 g/mol
- The molar mass of S = 32.06 g/mol
- The molar mass of O = 16.00 g/mol
- Multiply the respective atomic masses by the number of atoms in the formula, then add them together:
Molar mass of CuSO4 = 63.55 g/mol + 32.06 g/mol + 4 * 16.00 g/mol
= 159.61 g/mol

2. Calculate the moles of CuSO4 required using the molar concentration formula.
- Molar concentration (M) is given as 3.0 M, which means there are 3.0 moles of CuSO4 in 1 liter of solution.
- Moles of CuSO4 = Molar concentration (M) × Volume (L)
= 3.0 mol/L × 3.00 L
= 9.0 mol

3. Convert moles of CuSO4 to grams using the molar mass of CuSO4.
- Grams of CuSO4 = Moles of CuSO4 × Molar mass of CuSO4
= 9.0 mol × 159.61 g/mol
= 1,436.49 g

Therefore, you would need 1,436.49 grams of Copper(II) Sulfate (CuSO4) to make a 3.00 L solution with a concentration of 3.0 M.