How much work is needed to move a -8.00 uC charge from the ground to a point whose potential is +75.0V ?
I know -8.00 uc = -0.8 x 10^-6 then I used
W = Fd but I can't seems to get right answer any hint is appreciated.
To calculate the work required to move a charge from one point to another, you need to use the formula:
W = q ∆V
where W represents the work done, q is the charge being moved, and ∆V is the change in voltage.
In this case, you have a charge of -8.00 uC (-0.8 x 10^-6 C) being moved from the ground to a point with a potential of +75.0V.
To find the work required, substitute the values into the formula:
W = (-0.8 x 10^-6 C) (75.0V)
Now, calculate the result:
W = -6.0 x 10^-5 J
Therefore, the work required to move the -8.00 uC charge from the ground to a point with a potential of +75.0V is -6.0 x 10^-5 Joules.