a bag of fruit contains 4 apples, 1 plum, 2 apricots, 3 oranges. Pieces of fruit are drawn twice with replacement. What is p(apple, then apricot)?
4/5, 2/25, 3/25, 3/5
I chose 3/5.
I need some help please.
10 pieces of fruit, 4 apples and 2 apric.
prob(apple, then appricot)
= (4/10)(2/10)
= 8/100
= 2/25
how did you get 3/5 ?
6 apple ,3 gauvas and 1 orange.what is the probability that a fruit selected at random is an apple
Answer: 3/25.
thx guys! <3
To find the probability of drawing an apple first and then an apricot, we need to calculate the probability of drawing an apple and then multiplying it by the probability of drawing an apricot.
First, let's consider the probability of drawing an apple. There are a total of 4 apples in the bag, and we are drawing twice with replacement. This means that after each draw, we put the fruit back into the bag before drawing again. So, the probability of drawing an apple on the first draw is 4/10 (since there are 10 pieces of fruit in total).
Next, let's consider the probability of drawing an apricot. There are a total of 2 apricots in the bag, and we are drawing twice with replacement. So, the probability of drawing an apricot on the second draw is also 2/10.
To find the probability of both events happening, we multiply the individual probabilities: (4/10) * (2/10) = 8/100 = 2/25.
Therefore, the correct answer is 2/25, not 3/5.