How do I calculate the molality of a saturated solution of KCl at 70 degrees Celsius? I have gotten the moles of KCl (.66) but am not sure where to go from there.
m = mols/kg solvent = 0.66/kg solvent.
To calculate the molality of a saturated solution of KCl at 70 degrees Celsius, you will need to know the mass of the solvent (typically water) in kilograms.
Once you have the mass of the solvent, you can use the following formula to calculate molality:
Molality (m) = moles of solute / mass of solvent (in kg)
Given that you already have the moles of KCl (0.66), you now need to determine the mass of the solvent.
If you do not have this information, you can assume a value of 1 kg for simplicity (this approximation may slightly affect the accuracy of your final result).
Using the assumed mass of 1 kg as an example, the calculation would look like this:
Molality (m) = 0.66 moles / 1 kg = 0.66 mol/kg
Therefore, the molality of the saturated solution of KCl at 70 degrees Celsius would be 0.66 mol/kg.
To calculate the molality (m) of a solution, you need to divide the moles of solute by the mass (in kilograms) of the solvent.
To find the molality of a saturated solution of KCl at 70 degrees Celsius, you already have the moles of KCl (.66). Now, you need to determine the mass of the solvent.
To do this, you'll need to know the density of the solvent at that temperature. Assuming the solvent is water, you can use density tables or formulas to find the density at 70 degrees Celsius. Let's say the density of water at 70 degrees Celsius is 0.990 g/mL or 0.990 kg/L (kilograms per liter).
Now, to calculate the mass of the solvent, you'll need to know the volume of the solvent that contains the KCl. Let's assume that you have 1 liter of solution.
The mass of the solvent can be calculated by multiplying the volume of the solvent (in liters) by its density (in kilograms per liter). In this case, the mass of the solvent would be 1 liter * 0.990 kg/L = 0.990 kilograms.
Now that you have the moles of KCl (.66) and the mass of the solvent (0.990 kg), you can calculate the molality using the formula:
m = moles of solute / mass of solvent
m = 0.66 mol / 0.990 kg = 0.67 mol/kg
Therefore, the molality of the saturated solution of KCl at 70 degrees Celsius would be 0.67 mol/kg.