Three indviduals form a partnership and agree to divide the profits equally. X invests $6,500, Y invests $2,000, and Z invests $1,500. If the profits are $3,000, how much less does X receive then if the profits were divided in proportion to the amount invested?
In printing an article of 24,000 words, a printer decides to use two sizes of type. Using the larger type, a printed page contains 1,200 words. Using the smaller type, a page contains 1,500 words. The article is allotted 17 full pages in a magazine. How many pages must be in small type?
by amount invested...
total investment: 10,000
X=3000*6500/10000
Y=3000*2000/10000
and so on.
b. 24000=1200*L + 1500*S
S+L=17
can you solve it now?
dont understand
1500x + 1200y = 30000 -1500 =28,500
1500x=28500
x=19?
X =19. That's wrong.
To find the answer to the first question, we need to calculate the share of each partner based on the amount invested.
First, let's calculate the total investment:
X invested $6,500.
Y invested $2,000.
Z invested $1,500.
Total investment = $6,500 + $2,000 + $1,500 = $10,000.
Now, let's calculate the share of each partner based on the amount invested:
X's share = (X's investment / Total investment) * Total profits
X's share = ($6,500 / $10,000) * $3,000 = $1,950.
Similarly, we can calculate the shares for Y and Z:
Y's share = (Y's investment / Total investment) * Total profits
Y's share = ($2,000 / $10,000) * $3,000 = $600.
Z's share = (Z's investment / Total investment) * Total profits
Z's share = ($1,500 / $10,000) * $3,000 = $450.
Now, let's calculate how much less X receives than if the profits were divided proportionally to the amount invested:
Difference = X's share - X's proportional share
Difference = $1,950 - (X's investment / Total investment) * Total profits
Difference = $1,950 - ($6,500 / $10,000) * $3,000