How much water must be added to make 500 ml of 12.0 M HCl to 1.0 M HCl
(500mL• 12M) / 1.0M
=6000m
Is this correct?
What's 6000m. Did you mean 6000 mL? That is the TOTAL volume needed; the question wants to know how much must be ADDED so you must add 6000 mL - 500 you already had = 5500 mL to be added.
To solve this question, you need to use the formula:
C1V1 = C2V2
Where:
C1 = Initial concentration of the solution (12.0 M HCl)
V1 = Initial volume of the solution (unknown)
C2 = Final concentration of the solution (1.0 M HCl)
V2 = Final volume of the solution (500 mL)
Rearranging the formula, we have:
V1 = (C2V2) / C1
Substituting the given values:
V1 = (1.0 M * 500 mL) / 12.0 M
V1 = 41.67 mL
Therefore, you need to add approximately 41.67 mL of water to 500 mL of 12.0 M HCl solution to obtain a 1.0 M HCl solution.
So, no, 6000 mL is not the correct answer.