A $10 bottle of detergent yields 10 loads of laundry. Allen tries this detergent & finds he can do only 8 loads of laundry from 1 bottle. What fraction of the advertised # of loads was he able to do?

He was able to do 8 out of 10, which would be 8/10, which could be further reduced to 4/5

Thanks, that was exactly the answer I was looking for. You are a genius whoever you are.

To find the fraction of the advertised number of loads Allen was able to do, we need to divide the number of loads he actually did by the advertised number of loads.

Number of loads Allen actually did = 8
Advertised number of loads = 10

Now, let's calculate the fraction:

Fraction of the advertised number of loads = (Number of loads Allen actually did) / (Advertised number of loads)
Fraction of the advertised number of loads = 8 / 10
Fraction of the advertised number of loads = 4/5

So, Allen was able to do 4/5 or 80% of the advertised number of loads.

To find the fraction of the advertised number of loads that Allen was able to do, we can use the following formula:

Fraction = (Number of loads done / Advertised number of loads)

In this case, the advertised number of loads is 10, and Allen was only able to do 8 loads. Plugging this into the formula, we get:

Fraction = (8 / 10)

To simplify this fraction, we can divide both the numerator and denominator by their greatest common divisor. In this case, the GCD of 8 and 10 is 2:

Fraction = (4 / 5)

Therefore, Allen was able to do 4/5 or 80% of the advertised number of loads.