20 g NaOH are dissolved in 1 L H2O. What is the N of the NaOH solution?
N stands for sodium, all though I bet you meant Na. I'm sorry if this is incorrect.
See your post above.
To determine the normality (N) of a solution, you need to know the number of equivalents (eq) of the solute present per liter of solution. For acids and bases, the number of equivalents is determined by the number of moles of protons (H+) or hydroxide ions (OH-) that can be donated or accepted by the solute.
For NaOH, it is a strong base that can donate one hydroxide ion (OH-) per molecule. Therefore, the number of equivalents of NaOH is equal to the number of moles of NaOH.
To calculate the number of moles of NaOH, you can use the given mass of NaOH and its molar mass. The molar mass of NaOH is the sum of the atomic masses of sodium (Na), oxygen (O), and hydrogen (H). The atomic masses are as follows:
Na: 22.99 g/mol
O: 16.00 g/mol
H: 1.01 g/mol
So, the molar mass of NaOH is 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 39.00 g/mol.
Now, divide the given mass of NaOH by its molar mass to get the number of moles:
20 g NaOH / 39.00 g/mol = 0.513 mol NaOH
Since the number of equivalents is equal to the number of moles for NaOH, we have 0.513 eq NaOH.
Finally, to calculate the normality (N), divide the number of equivalents by the volume of the solution in liters:
N = 0.513 eq / 1 L = 0.513 N
Therefore, the normality of the NaOH solution is 0.513 N.