Copper dissolves in dilute acid ( H2so4) to form a pale blue solution

Which of the following equation is correct

1) Cu + H2sO4-----> CuSO4 + h2
2) Cu + 2H2so4--->Cuso4 + 2H20 + 2SO2

I have news for you. Copper will not dissolve in H2SO4 unless it is heated. If heated it will react but it does not produce H2 gas. It produces SO2. So which equation is right?

no 2 obviously

right. Note that Cu is below hydrogen in the activity series; therefore, it will not displace hydrogen from the acid. What you get is an oxidiation/reduction reaction in which the Cu is oxidized to Cu^2+ and the H2SO4 is reduced to SO2. But that only happens if the H2SO4 is heated. The same kind of thing happens with HNO3 but the reaction is much more vigorous and it happens in the cold and in dilute or concentrated acid. Cu is oxidized to Cu^2+ and HNO3 is reduced to either NO or NO2 depending upon whether dilute or concentrated HNO3 is used.

Thak you sir for all these momentous information. Can you help me with one more question. I have posted it just now sir.

I have an important exam tomorrow
The question being ;
Methane burns in air to give carbon dioxide and water. Give a chemical equation . Show(State ) how the mixtures of these gases can be separated

Responded above. Good luck on the exam.

To determine the correct equation for the reaction between copper (Cu) and dilute sulfuric acid (H2SO4), we need to consider the oxidation states of the elements involved as well as the conservation of atoms.

The first equation you provided is incorrect because it does not balance the atoms on both sides of the equation. Additionally, it does not account for the formation of sulfuric acid products.

The second equation you provided is correct:

Cu + 2H2SO4 → CuSO4 + 2H2O + SO2

In this equation, copper reacts with two molecules of sulfuric acid. As a result, copper sulfate (CuSO4), water (H2O), and sulfur dioxide (SO2) are formed. It is important to note that the presence of dilute acid in this reaction facilitates the dissolution of copper and leads to the formation of a pale blue solution of copper sulfate.