A line has a slope of 2. It passes through the points (1,2) and (3,y). What is he value of y?
can someone walk me through this without using y=mx+b?
well, let's just take the slope using the 2 given points
slope = (y-2)/(3-1) = (y-2)/2
but we are told that the slope is 2 , so
(y-2)/2 = 2
y-2 = 4
y = 6
To find the value of y, given that the line has a slope of 2 and passes through the points (1,2) and (3,y), we can use the formula for slope:
slope = (change in y) / (change in x)
In this case, the change in y is y - 2 and the change in x is 3 - 1. Since the slope is given as 2, we can set up the equation:
2 = (y - 2) / (3 - 1)
Now, we can cross multiply:
2(3 - 1) = y - 2
2(2) = y - 2
4 = y - 2
Finally, we isolate y by adding 2 to both sides of the equation:
4 + 2 = y
6 = y
Therefore, the value of y is 6.
Sure! To find the value of y, we can use the formula for the slope of a line which is:
slope = (change in y) / (change in x)
First, let's calculate the change in y and change in x.
Change in x = x2 - x1 = 3 - 1 = 2
Since the line passes through the points (1, 2) and (3, y), we need to find the change in y.
slope = (change in y) / (change in x)
2 = (change in y) / 2
To solve for the change in y, multiply both sides of the equation by 2:
2 * 2 = change in y
So, the change in y is equal to 4.
Now, we can find the value of y by adding the change in y to the y-coordinate of one of the points (1, 2):
y = 2 + 4
Thus, the value of y is 6.