The legs of an isosceles triangle are 0.3 foot less than twice the base. The perimeter of the triangle is 4.9 feet.
What is the length of one of the triangle’s legs?
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To find the length of one of the triangle's legs, we can set up an equation using the given information.
Let's assume the base of the triangle is x feet.
According to the problem, the legs of the isosceles triangle are 0.3 foot less than twice the base. This can be expressed as (2x - 0.3) feet.
The perimeter of a triangle is the sum of all its sides. In this case, the perimeter is given as 4.9 feet. So, we can set up the equation:
Base + Leg + Leg = Perimeter
x + (2x - 0.3) + (2x - 0.3) = 4.9
Now, solve the equation to find the value of x.
x + 2x - 0.3 + 2x - 0.3 = 4.9
5x - 0.6 = 4.9
5x = 5.5
x = 5.5 / 5
x = 1.1
Therefore, the length of one of the triangle's legs is given by 2x - 0.3:
2(1.1) - 0.3 = 2.2 - 0.3 = 1.9 feet
So, the length of one of the triangle's legs is 1.9 feet.
b + 2(2b-0.3) = 4.9
That gives the base; now figure the legs.