Molarity

What is the final volume (in Liters) of a solution prepared by diluting 25 mL of 8.25 M sodium hydroxide to a concentration of 2.40 M?

mL1 x M1 = mL2 x M2

Dilution formula:

M1 * V1 = M2 * V2
where
M = molarity
V = volume

Substitute:
8.25 M * 25 mL = 2.40 M * V2

Now solve for V2 and don't forget to convert it to Liters.

To find the final volume of the solution, we can use the equation for dilution:

M1V1 = M2V2

Where:
M1 = initial molarity of the solution
V1 = initial volume of the solution
M2 = final molarity of the solution
V2 = final volume of the solution

We are given:
M1 = 8.25 M
V1 = 25 mL (which is equivalent to 0.025 L)
M2 = 2.40 M

Let's plug the values into the equation and solve for V2:

(8.25 M)(0.025 L) = (2.40 M)(V2)

0.20625 L = 2.40 M(V2)

Divide both sides of the equation by 2.40 M:

0.20625 L / 2.40 M = V2

V2 ≈ 0.086 L

Therefore, the final volume of the solution is approximately 0.086 liters.

To calculate the final volume of a solution when diluting a solution from one concentration to another, you can use the dilution formula:

C1V1 = C2V2

Where:
C1 = initial concentration of the solution (in Molarity)
V1 = initial volume of the solution (in liters)
C2 = final concentration of the solution (in Molarity)
V2 = final volume of the solution (in liters)

In this case, the initial concentration (C1) is 8.25 M, the initial volume (V1) is 25 mL, the final concentration (C2) is 2.40 M, and we need to find the final volume (V2).

First, convert the initial volume (V1) from milliliters to liters:
V1 = 25 mL = 25/1000 = 0.025 L

Now, substitute the values into the dilution formula:
8.25 M x 0.025 L = 2.40 M x V2

Solving for V2:
V2 = (8.25 M x 0.025 L) / 2.40 M
V2 = 0.08625 L

Therefore, the final volume of the solution, when diluted from 25 mL of 8.25 M sodium hydroxide to a concentration of 2.40 M, is 0.08625 liters.