Calculate the H+ of 0.1 M NaOH
Calculate the pH of 0.1 M NaOH
[H+]=10^ph
[H+]=10^-13
[H+]=1*10^-13M
Since pH+ pOH=14
pH= -log (0.1M)
pH=1
so 14-1
pH= 13
first: OH=.1M
pOH=-logOH=1
PH=14-pOH=13
H*OH=10^-14
H=1/10 * 10^-14=10^-13
Surely you meant for one of those lines to read pOH. I don't follow your work but the bottom line is right.
If yu have 0.1M NaOH, then OH = 0.1, pOH is 1, which makes pH = 13. In that first line it should be (H^+) = 10^-pH
To calculate the H+ concentration of a 0.1 M NaOH solution, we need to determine the concentration of H+ ions in the solution. NaOH is a strong base that dissociates completely in water, so it produces equal moles of Na+ and OH- ions.
Since the concentration of NaOH is 0.1 M, the concentration of OH- ions is also 0.1 M.
Now, we can use the fact that [H+] x [OH-] = 1.0 x 10^-14 M^2 (at 25 degrees Celsius) to find the concentration of H+. Since the concentration of OH- is 0.1 M, we can substitute this value into the equation:
[H+] x 0.1 M = 1.0 x 10^-14 M^2
Solving for [H+],
[H+] = (1.0 x 10^-14 M^2) / 0.1 M
[H+] = 1.0 x 10^-13 M
Therefore, the concentration of H+ ions in a 0.1 M NaOH solution is 1.0 x 10^-13 M.
To calculate the H+ concentration of 0.1 M NaOH, we need to understand that NaOH is a strong base that completely dissociates in water to form Na+ and OH- ions. The H+ concentration in a solution is directly related to the OH- concentration.
In the case of NaOH, when it dissolves, it forms OH- ions. Since NaOH is a strong base, it completely dissociates, resulting in an equal concentration of OH- ions. Therefore, the concentration of OH- in 0.1 M NaOH is also 0.1 M.
To calculate the H+ concentration (also known as the [H+]), we can use the equation [H+] = 10^-pOH. In this case, since the concentration of OH- is 0.1 M, we can find the pOH value by taking the negative logarithm of 0.1:
pOH = -log(0.1)
pOH ≈ 1
Now, knowing that pH + pOH = 14, we can find the pH. By subtracting the pOH value from 14, we get:
pH = 14 - 1
pH = 13
Therefore, the pH of a solution with 0.1 M NaOH is 13.