A uniform plank of a seesaw is 5 meter long and supported at its centre.a boy weighing 40kgf sits at a distance 1.5meter from one end of the seesaw.where must a girl weighing 25kgf sit on the other end of the seesaw so as to balance the boy.

if an ideal machine ma=vr=5. if the efficiency of a machine is 80% the how much 'e' does one have do put to raise the load of 100 n

To balance the seesaw, we need to make sure that the torque on both sides of the pivot point is equal. Torque is calculated by multiplying the weight of an object by its distance from the pivot point.

Let's assume the position of the girl on the other end of the seesaw is x meters from the pivot point.

The torque on the boy's side can be calculated as follows:
Torque_boy = Weight_boy * Distance_boy
= 40kgf * 1.5m

Since torque is equal on both sides of the seesaw, the torque on the girl's side can be calculated as:
Torque_girl = Weight_girl * Distance_girl
= 25kgf * x

Setting these two torques equal to each other, we get:
40kgf * 1.5m = 25kgf * x

Simplifying, we have:
60kgf = 25kgf * x

Dividing both sides by 25kgf, we find:
x = 2.4m

Therefore, the girl should sit 2.4 meters from the other end of the seesaw in order to balance the boy.

To balance the see-saw, the torque on both sides should be equal. Torque is calculated by multiplying the force applied by the distance from the pivot point.

Let's assume the girl sits at a distance of 'x' meters from the other end of the see-saw.

The torque exerted by the boy (40kgf) is calculated as:
Torque_boy = Weight_boy * Distance_boy
Torque_boy = 40kgf * 1.5m

The torque exerted by the girl (25kgf) is calculated as:
Torque_girl = Weight_girl * Distance_girl
Torque_girl = 25kgf * x

Since the see-saw is balanced, the torque exerted by the boy should be equal to the torque exerted by the girl.
So, we can set up the equation:
40kgf * 1.5m = 25kgf * x

Now, we can solve for 'x':
(40kgf * 1.5m) / 25kgf = x

Simplifying the equation:
60kgf * m / 25kgf = x
24m / 25 = x

Therefore, the girl must sit at a distance of 24/25 meters (or 0.96 meters) from the other end of the see-saw in order to balance the boy.

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Each side is 2.5 m.The 40 kg boy is 1.5m from the end or 1m from the center.
40*1 = 25*x
x is the distance from the center to the girl.