Susan pulls on a rope sleigh with a force of 120 N. If the rope makes an angle of 25 degrees with the horizontal, what is the force that tends to lift the sleigh?
a)120.00 N
b)108.76 N
c)50.71 N
d)84.85 N
how would you know?
50.71N
Well, Susan seems like a strong lady, but unfortunately, I don't have eyes to witness her pulling on that rope. However, I can still help you with the math involved!
To find the force that tends to lift the sleigh, we need to calculate the component of Susan's force that acts in the upward direction. This can be done using trigonometry.
The force that tends to lift the sleigh (F_lift) can be found using the equation:
F_lift = F_pull * sin(angle)
where F_pull is the force Susan is pulling with, and angle is the angle the rope makes with the horizontal.
So, let's plug in the values:
F_pull = 120 N (as given)
angle = 25 degrees (as given)
Using a scientific calculator or an online trigonometry calculator, we can find:
sin(25 degrees) ≈ 0.42262
Now, let's calculate:
F_lift = 120 N * 0.42262 ≈ 50.71 N
So, the force that tends to lift the sleigh is approximately 50.71 N. That makes the answer c) 50.71 N.
I hope that helps! Let me know if you have any more questions or if you want another joke along the way!
To find the force that tends to lift the sleigh, we need to determine the component of the force acting in the vertical direction. This can be calculated using the formula:
Vertical force = Force * sin(angle)
Here, the force is 120 N and the angle is 25 degrees. Plugging these values into the formula, we get:
Vertical force = 120 N * sin(25 degrees)
Using a calculator, the value of sin(25 degrees) is approximately 0.423.
Vertical force = 120 N * 0.423
Vertical force ≈ 50.71 N
Therefore, the force that tends to lift the sleigh is approximately 50.71 N.
The correct answer is option c) 50.71 N.
To determine the force that tends to lift the sleigh, we need to find the vertical component of the force Susan applies to the rope. We can do this by using trigonometry.
First, we need to find the vertical component of the force Susan applies to the rope. This can be done using the formula:
Vertical component = Force * sin(angle)
In this case, Susan applies a force of 120 N and the angle with the horizontal is 25 degrees. Plugging in the values into the formula, we get:
Vertical component = 120 N * sin(25 degrees)
Using a scientific calculator, we can calculate sin(25 degrees) = 0.4226. Multiplying this value by 120 N, we get:
Vertical component ≈ 120 N * 0.4226 ≈ 50.71 N
Therefore, the force that tends to lift the sleigh is approximately 50.71 N.
So, the correct answer is c) 50.71 N.
120 sin 25°
think about it -- a horizontal force (0°) does no lifting, and an upward force (90°) is all lift.