Math

posted by Tika

Please help me write this as a single fraction? Sorry my addition/equal key does not work



- 3a-7b/2a plus 5a-4b/3a plus 3.

  1. Steve

    -(3a-7b)/(2a) + (5a-4b)/(3a) + 3

    The common denominator is (2a)(3a), so we have for the numerator

    -(3a-7b)(3a) + (5a-4b)(2a) + 3(2a)(3a)
    = 19a^2+13ab

    so, our final fraction is

    (19a^2+13ab)/6a^2 = (19a+13b)/(6a)

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