Solve by using the quadratic formula
7x^2-5x=0
a=7
b = -5
c=0, so
x = (5±√(25-0))/14 = (5±5)/14
x = 0 or 5/7
But then, we saw that just by factoring:
x(7x-5) = 0
7x^2-5x=0
b = -5
c=0, so
x = (5±√(25-0))/14 = (5±5)/14
x = 0 or 5/7
But then, we saw that just by factoring:
x(7x-5) = 0