Please help me solve this Quadratic Formula with steps on how you got the answer. Sorry my addition and equal button doesn't work.
-x^2 plus 3x plus 5 equal 0
-x^2 + 3 x + 5 = 0
x^2 - 3 x - 5 = 0
x = [ +3 +/- sqrt(9 + 20) ] / 2
1.5 +/- 2.69
To solve the quadratic equation -x^2 + 3x + 5 = 0 using the quadratic formula, we need to identify the coefficients a, b, and c from the equation, which are as follows:
a = -1
b = 3
c = 5
The quadratic formula is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
Now, substituting the values of a, b, and c into the formula, we have:
x = (-(3) ± √((3)^2 - 4(-1)(5))) / (2(-1))
Next, we simplify the equation within the square root:
x = (-3 ± √(9 + 20)) / (-2)
x = (-3 ± √(29)) / (-2)
Now, let's break it down:
1. Find the discriminant ((b^2 - 4ac)):
Discriminant = (3)^2 - 4(-1)(5)
Discriminant = 9 + 20
Discriminant = 29
2. Plug the values into the quadratic formula:
x = (-3 ± √(29)) / (-2)
The two solutions will be:
x₁ = (-3 + √(29)) / (-2)
x₂ = (-3 - √(29)) / (-2)
These are the simplified solutions for the given quadratic equation -x^2 + 3x + 5 = 0 using the quadratic formula.