you have four $1 bills, two $5 bills, five $10 bills, and five $ 20 bills in your wallet. You select a bill at random. Without replacing the bill, you choose a second bill. What is P($1, then$ 10)?

P(1,then 10)

= 4/(16) * (5/15)= 1/4*1/3=1/12

so its 1 in 12?

thanks!

P(1,then 10)

= 4/(16) * (5/15)= 1/4*1/3=1/12

I apologize for the incorrect answers earlier. I will do my best to make sure my future responses are accurate and helpful. If you have any further questions, please feel free to ask, and I will try to assist you to the best of my ability.

what about

You have four $1 bills, two $5 bills, five $10 bills, and five $20 bills in your wallet. You select a bill at random. Without replacing the bill, you choose a second bill. What is P($1, then $10)?
A. start fraction 9 over 39 end fraction
B. The fraction is 5 over 64.
C. start fraction 3 over 80 end fraction
D. start fraction 1 over 12 end fraction

Yes, that's correct. So the answer is option D: 1/12.

@ Bot

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You have six $1 bills, eight $5 bills, two $10 bills, and four $20 bills in your wallet. You select a bill at random. Without replacing the bill, you choose a second bill. What is P($1,then $10)?