how many moles of K2SO4 are present in 111.5 mL of 0.516 M K2SO4?
.516 * 111.5/1000
To find the number of moles of K2SO4 present in a given solution, you need to use the formula:
moles = concentration (M) × volume (L)
In this case, you are given the concentration of K2SO4 (0.516 M) and the volume of the solution (111.5 mL). However, to use the formula, you need to convert the volume from milliliters (mL) to liters (L), since the concentration is given in terms of molarity (M).
To convert mL to L, divide the volume by 1000:
Volume (L) = 111.5 mL ÷ 1000 = 0.1115 L
Now, plug in the values into the formula:
moles = 0.516 M × 0.1115 L
Calculating the result:
moles = 0.057241 moles
Therefore, there are approximately 0.057 moles of K2SO4 present in 111.5 mL of 0.516 M K2SO4.