Cell respiration glucose is reacted wth oxygen in body to produce carbon dioxide and water how many liters of carbon dioxide would be produced if 90.0 g of glucose completely reacts with oxygen
C6H12O6(s)+ 6O2(g) -> 6H2O(g) + 6CO2 (g)
How many liters of carbon dioxide would be produced if 90.0 g of glucose completely reacts with oxygen
C'mon John, Bob Pursley told you how to work the problem, I showed you in more detail how to do it, now this is the second post after all of that. You've had all of the help you can get from us EXCEPT I shall be happy to explain anything you don't understand. The rules are that you must explain in detail what you don't understand and post your work up to this point. It would help if you told us why you don't know how to do the next step.
To calculate the number of liters of carbon dioxide produced when 90.0 g of glucose completely reacts with oxygen, we need to use the balanced chemical equation and the molar mass of glucose.
The balanced chemical equation is:
C6H12O6(s) + 6O2(g) -> 6H2O(g) + 6CO2(g)
The molar mass of glucose is 180.16 g/mol. From this, we can calculate the number of moles of glucose:
Number of moles of glucose = Mass of glucose / Molar mass of glucose
= 90.0 g / 180.16 g/mol
= 0.4996 mol (approximately)
From the balanced chemical equation, we can see that 1 mol of glucose produces 6 moles of carbon dioxide. Therefore, the number of moles of carbon dioxide produced is:
Number of moles of carbon dioxide = Number of moles of glucose x 6
= 0.4996 mol x 6
= 2.9976 mol (approximately)
Finally, we can convert the number of moles of carbon dioxide to liters using the ideal gas law, where 1 mol of gas occupies 22.4 liters at standard temperature and pressure (STP).
Number of liters of carbon dioxide = Number of moles of carbon dioxide x 22.4 liters/mol
= 2.9976 mol x 22.4 liters/mol
= 67.11 liters (approximately)
Therefore, if 90.0 g of glucose completely reacts with oxygen, approximately 67.11 liters of carbon dioxide would be produced.