Cell respiration glucose is reacted wth oxygen in body to produce carbon dioxide and water how many liters of carbon dioxide would be produced if 90.0 g of glucose completely reacts with oxygen
write and balance the equation.
C6H12O6+6O2>>>6CO2 + 6H20 check that
so how many moles is 90 grams of glucose?
You get six times as many moles of Carbon dioxide. Now the volume in liters depends on temperature and pressure.
To determine the number of liters of carbon dioxide produced when 90.0 g of glucose completely reacts with oxygen, we need to utilize stoichiometry.
1. Write the balanced chemical equation for cellular respiration:
C6H12O6 + 6O2 -> 6CO2 + 6H2O
According to this equation, one mole of glucose reacts with six moles of oxygen to produce six moles of carbon dioxide.
2. Calculate the moles of glucose:
To find the moles of glucose, divide the given mass (90.0 g) by the molar mass of glucose (180.16 g/mol):
90.0 g / 180.16 g/mol = 0.50 mol
3. Determine the moles of carbon dioxide:
Since the ratio of glucose to carbon dioxide is 1:6, the moles of carbon dioxide produced will be six times the moles of glucose:
0.50 mol glucose × 6 mol CO2/mol glucose = 3 mol CO2
4. Convert the moles of carbon dioxide to liters:
At standard temperature and pressure (STP), one mole of any gas occupies 22.4 liters. Therefore, 3 moles of carbon dioxide will occupy:
3 mol × 22.4 L/mol = 67.2 L
Therefore, when 90.0 g of glucose completely reacts with oxygen, it will produce approximately 67.2 liters of carbon dioxide.