The weight of one atom of uranium is 238amu. Its actual weight is ......g.
I showed you how to do that when you first posted. All you need to do is punch those numbers into your calculator. I'll be glad to explain anything you don't understand but re-posting the question doesn't do any good and wastes our time.
3.95*10(-22)
397.46×10 E-24
To find the actual weight of one atom of uranium in grams, you can use the concept of atomic mass units (amu) and the Avogadro constant.
1. Start with the given information that the weight of one atom of uranium is 238 amu.
2. Find the molar mass of uranium by using the periodic table or a reliable source. The molar mass of uranium (U) is approximately 238.02891 grams/mole.
3. The molar mass expressed in grams/mole represents the weight of one mole of uranium atoms.
4. The Avogadro constant, denoted by the symbol "NA," is a conversion factor that gives the number of atoms or molecules in one mole of a substance, which is approximately equal to 6.022 × 10^23 particles/mole.
5. Using these conversion factors, you can calculate the actual weight (in grams) of one atom of uranium by setting up the following equation:
Actual weight of one atom of uranium (grams) = molar mass of uranium (grams/mole) / Avogadro constant (particles/mole)
Substituting the values:
Actual weight of one atom of uranium (grams) = 238.02891 g/mole / (6.022 × 10^23 particles/mole)
Using a calculator, the actual weight of one atom of uranium is approximately 3.95 × 10^-22 grams.