How many moles of chlorine are there in 16.0 mL of 0.450 M CaCl2?
0.0072 mol
0.0144 mol
0.0216 mol
0.0375 mol
none of the above
I had chose 0.0072 and had submitted it in my assignment, but it had said it was wrong. I chose 0.0072 because I did this equation: 16/ 1000*0.450 and got 0.0072.
I got to agree that it is 0.0072
but that is wrong when entered into assignment, what else could it be
then you must times it by two so it would be .0144
To determine how many moles of chlorine are present in 16.0 mL of 0.450 M CaCl2, we first need to understand the chemical formula of calcium chloride (CaCl2).
CaCl2 consists of one calcium ion (Ca2+) and two chloride ions (Cl-). This means that for every one mole of CaCl2, there are two moles of Cl- ions.
In the given solution, 0.450 M represents the concentration of CaCl2. This means there are 0.450 moles of CaCl2 dissolved in 1 liter (1000 mL) of solution.
To find the number of moles of chlorine (Cl-) in the solution, we need to consider the stoichiometry of the compound. Since there are two chloride ions for every one mole of CaCl2, the number of moles of chloride ions is twice the number of moles of CaCl2.
We can calculate the moles of CaCl2 in 16.0 mL of the solution as follows:
moles of CaCl2 = volume (in liters) x concentration
= 16.0 mL / 1000 mL/L x 0.450 mol/L
= 0.0072 mol
However, we need to find the moles of chlorine ions (Cl-) rather than CaCl2. Since there are two moles of Cl- for every one mole of CaCl2, we multiply the moles of CaCl2 by 2:
moles of Cl- = 0.0072 mol x 2
= 0.0144 mol
Therefore, the correct answer is 0.0144 mol, not 0.0072 mol.