A 44.8−mL sample of a 7.0M KNO3 solution is diluted to 1.10L What volume of the diluted solution contains 16.0g of KNO3?

Would I do the same thing for this one or would does it have an extra step it it.

16 g KNO3/molar mass KNO3 = mols KNO3.

M of the diluted solution is
mL1 x M1 = mL2 x M2
44.8 x 7.0 = 1100 x M2
Solve for M2.
Then M = mols/L or L = mols/M. You know mols in the 16 g, you know M of the diluted solution, solve fo4 L of the diluted solution.

To find the volume of the diluted solution that contains 16.0g of KNO3, you need to use the concept of molarity (M) and the equation:

M1V1 = M2V2

where:
M1 = initial molarity of the solution before dilution (7.0M)
V1 = initial volume of the solution before dilution (44.8 mL or 0.0448 L)
M2 = final molarity of the diluted solution (unknown)
V2 = final volume of the diluted solution (what we want to find)

First, convert the initial volume (V1) to liters:

V1 = 44.8 mL × (1 L / 1000 mL) = 0.0448 L

Next, substitute the given values into the equation and solve for V2:

(7.0M) × (0.0448 L) = M2 × (1.10 L)

Now, solve for M2:

M2 = (7.0M × 0.0448 L) / (1.10 L)
M2 = 0.3024 M

The final molarity of the diluted solution is 0.3024 M.

Finally, you can use the concept of molarity to find the volume (V2) of the diluted solution that contains 16.0g of KNO3.

The molar mass of KNO3 is:
K = 39.1 g/mol
N = 14.0 g/mol
O = 16.0 g/mol (x3)

Add the molar masses together to find the molar mass of KNO3:
Molar mass of KNO3 = 39.1 g/mol + 14.0 g/mol + (16.0 g/mol × 3) = 101.1 g/mol

Now, you can calculate the number of moles of KNO3 present in 16.0g:

Number of moles = mass / molar mass
Number of moles = 16.0g / 101.1 g/mol = 0.158 mol

Finally, to find the volume (V2) of the diluted solution that contains 16.0g of KNO3, use the equation:

Molarity (M2) = moles (n) / volume (V2)

Rearranging the equation, we get:

V2 = n / M2

Substitute the values into the equation and solve for V2:

V2 = 0.158 mol / 0.3024 M
V2 ≈ 0.522 L

Therefore, approximately 0.522 liters (or 522 mL) of the diluted solution would contain 16.0g of KNO3.