pls...help, QUESTION = At what depth below the free surface of oil having a density of 600kg/m^3 will the pressure be equal to 1bar.
P = ρgh
where
P = pressure (in Pa)
g = acceleration due to gravity = 9.8 m/s^2
h = height (in meters)
Note that 1 bar = 100000 Pa. Substituting,
100000 = (600)(9.8)(h)
h = ?
Hope this helps~ `u`
very well,thank
To determine the depth below the free surface of oil where the pressure is equal to 1 bar, we can use the hydrostatic pressure equation. This equation relates the pressure at a certain depth in a fluid to the density and acceleration due to gravity.
The hydrostatic pressure equation is given by:
P = ρ * g * h
Where:
P is the pressure
ρ (rho) is the density of the fluid (in this case, oil) which is 600 kg/m^3
g is the acceleration due to gravity (approximately 9.8 m/s^2)
h is the depth below the free surface of the fluid (unknown)
To find h, we rearrange the equation to solve for it:
h = P / (ρ * g)
Plugging in the given values:
h = 1 bar / (600 kg/m^3 * 9.8 m/s^2)
First, let's convert 1 bar to pascals (Pa) since the SI unit of pressure is Pascal:
1 bar = 100,000 Pa
Now, substitute the values:
h = 100,000 Pa / (600 kg/m^3 * 9.8 m/s^2)
Performing the calculation:
h ≈ 17.1 meters
Therefore, the depth below the free surface of the oil where the pressure is equal to 1 bar is approximately 17.1 meters.