Which chemical equation shows that no atoms are lost during a chemical reaction?
A. 8Fe+s8-->Fe5
B. 8Fe+8S8--> 8FeS
C. Fe+8S8--->FeS
D. 8Fe+S8--->8FeS
Is the answer A?
it is D
No, the answer is not A. A chemical equation that shows that no atoms are lost during a chemical reaction must have the same number of each type of atom on both sides of the equation. Let's examine each option and analyze if they satisfy this condition:
A. 8Fe + S8 --> Fe5
In this equation, the reactant side has 8 iron (Fe) atoms and 8 sulfur (S) atoms, but the product side has only 5 iron atoms. Therefore, atoms are lost in this reaction.
B. 8Fe + 8S8 --> 8FeS
In this equation, the reactant side has 8 iron (Fe) atoms and 8 sulfur (S) atoms, and the product side also has 8 iron sulfide (FeS) molecules. The equation is balanced, so no atoms are lost. This option satisfies the condition.
C. Fe + 8S8 --> FeS
In this equation, the reactant side has 1 iron (Fe) atom and 8 sulfur (S) atoms, while the product side has only 1 iron sulfide (FeS) molecule. Therefore, atoms are lost in this reaction.
D. 8Fe + S8 --> 8FeS
In this equation, the reactant side has 8 iron (Fe) atoms and 1 sulfur (S) atom, while the product side has 8 iron sulfide (FeS) molecules. The equation is balanced, so no atoms are lost. This option satisfies the condition.
To summarize, the chemical equation that shows that no atoms are lost during a chemical reaction is option D: 8Fe + S8 --> 8FeS.
It can't possibly be A. Why?
There are 8 atoms Fe on the left and 5 on the right. There are 8 atoms S on the left and none on the right.
Don't guess. Count the atoms on the left and see if that number is on the right. If not that one can't be the answer.