How many seconds would it take an egg to hit the ground if it's at a 363 height range?
If 363 metres, solve
4.9t^2 = 363
if 363 ft, solve
16t^2 = 363
x/2=10+ 2y/3
To determine the time it takes for an object, like an egg, to fall from a certain height, we can use the laws of physics and the equation for freely falling objects.
The equation to calculate the time it takes for an object to fall from a height h is given by the formula:
t = √(2h/g)
Where:
t represents the time in seconds
h is the height in meters
g is the acceleration due to gravity, which is approximately 9.8 m/s² on Earth.
In this case, the height is given as 363, so we can plug this value into the equation:
t = √(2 * 363 / 9.8)
Simplifying the equation further:
t = √(726 / 9.8)
t = √74.08
t ≈ 8.6 seconds
Therefore, it would take approximately 8.6 seconds for the egg to hit the ground from a height of 363 units.