If you have a spinner with six spaces each with a letter P,U,I,O,E,N and you spin the spinner twice what is the P(vowel, then P)?
A.1/3
B.1/9
C.5/6
D.5/12
Is the answer D?
To find the probability of landing on P (vowel, then P) when spinning the spinner twice, we need to determine the number of favorable outcomes and the total number of possible outcomes.
The spinner has six spaces, each with a letter P, U, I, O, E, or N. This means that there are six possible outcomes for each spin.
For the first spin, we need to land on a vowel. There are three vowels among the six options (P, U, and O), so the probability of landing on a vowel on the first spin is 3/6 or 1/2.
Now, for the second spin, we need to land on the letter P. Since we already know the first spin resulted in a vowel, there are five remaining options for the second spin (P, I, O, E, and N). Therefore, the probability of landing on P on the second spin is 1/5.
To find the probability of both events happening, we multiply the probabilities of each event:
P(vowel, then P) = P(vowel) × P(P) = (1/2) × (1/5) = 1/10.
Therefore, the correct answer is not D (5/12), but rather:
A. 1/3
The answer is B.
Yes it's B. This is another example of conditional probability.
Note that there are four vowels here: U, I, O, E. And there are six letters total. So,
P(vowel) = 4/6
Then you spin again. The probability of getting a P:
P(P) = 1/6
Thus,
P(vowel, then P) = 4/6 * 1/6 = 4/36 = 1/9
hope this helps~ `u`
Thanks Jai for correcting me. I obviously read that too fast. Yes. All seems correct.
Thank you both for the help.
Explanation:
First time: 3/6 Which is 1/2 to land on a vowel.
Second time, 1/6 to land on P
(1/6) (1/2)