what mass of zinc dissolved in dilute HCL will produce 0.15g of hydrogen ?



can you explain the steps to sloving this question please

Sure, I'd be happy to help you with that! But first, let me clown around a bit with the question:

Why did the zinc go to school?
Because it wanted to be a dissolver!

Now, let's get serious and solve this problem step by step:

Step 1: Write the balanced chemical equation for the reaction between zinc and hydrochloric acid (HCl):

Zn + 2HCl → ZnCl2 + H2

From the equation, we know that 1 mole of zinc (Zn) reacts with 2 moles of hydrochloric acid (HCl) to produce 1 mole of hydrogen gas (H2).

Step 2: Calculate the molar mass of zinc (Zn):

The molar mass of zinc is 65.38 g/mol.

Step 3: Convert the given mass of hydrogen gas to moles:

Given mass of hydrogen gas = 0.15 g

Molar mass of hydrogen gas (H2) = 2 g/mol (2 hydrogens per molecule)

Number of moles = mass / molar mass
= 0.15 g / 2 g/mol
= 0.075 mol

Step 4: Use the stoichiometry of the balanced equation to find the moles of zinc:

According to the balanced equation, 1 mole of zinc reacts with 1 mole of hydrogen gas. In other words, the mole ratio of zinc to hydrogen is 1:1.

Therefore, the number of moles of zinc = 0.075 mol.

Step 5: Convert moles of zinc to mass:

Mass of zinc = number of moles × molar mass
= 0.075 mol × 65.38 g/mol
≈ 4.9045 g

So, approximately 4.9045 grams of zinc would dissolve in dilute HCl to produce 0.15 grams of hydrogen.

And remember, the most important step of all is to have a good laugh along the way!

To solve this question, we need to calculate the mass of zinc required to produce 0.15g of hydrogen gas.

Step 1: Determine the balanced chemical equation for the reaction between zinc (Zn) and hydrochloric acid (HCl).
The balanced chemical equation is:
Zn + 2HCl → ZnCl2 + H2

Step 2: Calculate the molar mass of hydrogen gas (H2).
The molar mass of H2 is 2g/mol.

Step 3: Use the stoichiometry of the balanced equation to find the molar ratio of zinc to hydrogen gas.
From the balanced equation, we can see that 1 mole of zinc reacts to produce 1 mole of hydrogen gas.

Step 4: Find the number of moles of hydrogen gas produced.
To find the number of moles, we can use the formula:
moles = mass / molar mass

moles of H2 = 0.15g / 2g/mol ≈ 0.075 mol

Step 5: Use the molar ratio from step 3 to find the number of moles of zinc required.
Since the molar ratio is 1:1 between zinc and hydrogen gas, the number of moles of zinc required will also be 0.075 mol.

Step 6: Find the molar mass of zinc (Zn).
The molar mass of Zn is 65.38g/mol.

Step 7: Calculate the mass of zinc required.
mass = moles × molar mass

mass of Zn = 0.075 mol × 65.38 g/mol ≈ 4.9045 g

So, to produce 0.15g of hydrogen gas, approximately 4.9045 grams of zinc needs to be dissolved in dilute HCl.

Sure! To solve this question, we need to use the concept of stoichiometry and molar ratios. Here are the steps to solve it:

Step 1: Write the balanced chemical equation.
In this case, the chemical equation is: Zn + 2HCl → ZnCl2 + H2
This equation shows that 1 mole of zinc reacts with 2 moles of hydrochloric acid to produce 1 mole of hydrogen gas.

Step 2: Calculate the molar mass of zinc.
The molar mass of zinc (Zn) is approximately 65.38 g/mol. This value can be found in the periodic table.

Step 3: Convert the mass of hydrogen gas to moles.
Given that the mass of hydrogen gas produced is 0.15 g, we need to convert it to moles. To do this, divide the mass by the molar mass of hydrogen (1.008 g/mol).

Moles of H2 = Mass of H2 / Molar mass of H2
= 0.15 g / 1.008 g/mol

Step 4: Determine the amount of zinc in moles.
Since the balanced equation tells us that 1 mole of zinc reacts with 1 mole of hydrogen gas, the amount of zinc (in moles) is equal to the amount of hydrogen gas (in moles).

Moles of zinc = Moles of H2

Step 5: Calculate the mass of zinc.
Now we can calculate the mass of zinc needed to produce the given amount of hydrogen gas. Multiply the moles of zinc by the molar mass of zinc.

Mass of zinc = Moles of zinc x Molar mass of zinc

By following these steps, you should be able to calculate the mass of zinc required to produce 0.15 g of hydrogen gas.

Write out the reaction:

ZN + 2 HCl --> ZNCl2 + H2

Covert g of H2 gas produced to moles:

0.15g of H2*(1 mole/2.016g)= moles of H2

moles of H2=moles of Zn

moles of Zn*(65.37g/mol)= g of Zn

Answer contains two significant figures

Conversely, this could have just been combined into one step;

0.15g of H2*(1 mole H2/2.016g)*(1 mol of Zn/1 mol of H2)*(65.37g Zn/mol)=g of Zn