what is the first step when solving x/15=3/5?
write a proportion using an unknown value x and the ratio 5:6 then solve it.
in an orchestra, the ratio of trombones to violas is 1 to 3.
a. there are 9 violas. write a proportion that gives the number t of trombones in the orchestra.
b. how many trombones are in the orchestra?
the school tam has 80 swimmers. the ration of grade 9 swimmers to all swimmers is 5:6. write a proportion that gives the number s of grade 9.
The first step when solving x/15 = 3/5 would be to cross-multiply.
To write a proportion using an unknown value x and the ratio 5:6, you can use the following: 5/6 = x/1. To solve it, cross-multiply and you get 6x = 5. Divide both sides of the equation by 6, and you find that x = 5/6.
For the orchestra question,
a. Since the ratio of trombones to violas is 1 to 3, and there are 9 violas, you can write the following proportion: 1/3 = t/9.
b. To find out how many trombones are in the orchestra, you can cross-multiply and solve the equation. So, 3t = 9, and when you divide both sides by 3, you find that t = 3.
For the swim team question, if the ratio of grade 9 swimmers to all swimmers is 5:6, you can write the following proportion: 5/6 = s/80.
The first step when solving the equation x/15 = 3/5 is to cross-multiply. Cross-multiplication involves multiplying the numerator of the first fraction by the denominator of the second fraction, and then multiplying the denominator of the first fraction by the numerator of the second fraction.
So, in this case, it would be (x * 5) = (15 * 3).
After cross-multiplying, you would get 5x = 45.
Next, divide both sides of the equation by 5 in order to isolate the variable x.
So, x = 45/5, which simplifies to x = 9.
Therefore, the solution to the equation x/15 = 3/5 is x = 9.
Now, let's move on to the next question.
a. To find the proportion that gives the number t of trombones in the orchestra, we can set up a ratio between the number of trombones and the number of violas.
Since the ratio of trombones to violas is 1 to 3, we can write it as: t/9 = 1/3.
b. To determine the number of trombones in the orchestra, we need to solve the proportion.
We can cross-multiply: t * 3 = 9 * 1.
So, 3t = 9.
Dividing both sides of the equation by 3 gives us: t = 9/3, which simplifies to t = 3.
Therefore, there are 3 trombones in the orchestra.
Moving on to the last question:
The ratio of grade 9 swimmers to all swimmers is 5:6. Let's represent the number of grade 9 swimmers with the variable s.
We can write the proportion as s/80 = 5/6.
To solve for the number of grade 9 swimmers, we will cross-multiply. This gives us 6s = 80 * 5.
Simplifying further, we get 6s = 400.
Finally, divide both sides of the equation by 6 to isolate the variable s. This gives us s = 400/6, which simplifies to s ≈ 66.67.
Therefore, there are approximately 66.67 grade 9 swimmers in the school team of 80 swimmers.
1. x/15 = 3/5
Here, all you do is multiply each side by 15. The end result is x = 9.
2. More specifics here are needed. The x could go on either side of the proportion and the x could have a higher value? is there?
3. 1:3 Ratio (1 Trombone for 3 Violas.
a. 3t = 9
b. 3
4. I actually don't know this one. I'm sorry. The answer though is ~66 people.