A compound has 85 % tin and 15% antimony. How many grams of antimony will be in 50. grams of the compound. My question is do I need to calculate the empirical formula first to do thi? I'm not sure where to start.
No. Tin and antimony are elements. Therefore their formulas (Tin- Sn | Antimony - Sb) are already in the simplest proportion formula wise. So that's the Empirical formula.
That's where you start and answers do you need the Empirical formula
I don't know that I buy the argument that SnSb is the empirical formula but I agree you don't need it.
To determine how many grams of antimony will be in 50 grams of the compound, you do not need to calculate the empirical formula first. You can directly calculate the amount of antimony in the compound using the given percentage composition.
To calculate the grams of antimony in 50 grams of the compound, follow these steps:
Step 1: Determine the percentage of antimony in the compound. The compound is stated to contain 15% antimony.
Step 2: Convert the percentage to a decimal by dividing it by 100:
15% = 15/100 = 0.15
Step 3: Calculate the grams of antimony in 50 grams of the compound using the percentage composition:
Grams of antimony = (0.15)(50 grams) = 7.5 grams
Therefore, there will be 7.5 grams of antimony in 50 grams of the compound.