Elin estimates her probability of passing French 0.6, passing chemistry is 0.8,

(a)determine the probability that elin will pass French but fail chemistry
(b) pass chemistry but fail French
(c) pass both classes
(d)fail both classes

b. 0.8*0.4=0.32

d. 0.4*0.2=0.8

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To determine the probabilities, we can use basic probability rules and calculations based on Elin's estimates.

(a) The probability that Elin will pass French but fail Chemistry can be calculated by multiplying the probability of passing French (0.6) with the probability of failing Chemistry (1 - 0.8 = 0.2).

Probability (Passing French and Failing Chemistry) = 0.6 * 0.2 = 0.12

So, the probability that Elin will pass French but fail Chemistry is 0.12, or 12%.

(b) Similarly, the probability that Elin will pass Chemistry but fail French can be calculated by multiplying the probability of passing Chemistry (0.8) with the probability of failing French (1 - 0.6 = 0.4).

Probability (Passing Chemistry and Failing French) = 0.8 * 0.4 = 0.32

So, the probability that Elin will pass Chemistry but fail French is 0.32, or 32%.

(c) To calculate the probability that Elin will pass both classes, we simply multiply the probabilities of passing French and passing Chemistry.

Probability (Passing Both Classes) = 0.6 * 0.8 = 0.48

So, the probability that Elin will pass both classes is 0.48, or 48%.

(d) Finally, to calculate the probability that Elin will fail both classes, we can subtract the probability of passing both classes (0.48) from 1.

Probability (Failing Both Classes) = 1 - 0.48 = 0.52

So, the probability that Elin will fail both classes is 0.52, or 52%.

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

A. .6 * (1-.8) = ?

C. .6 * .8 = ?

Use similar processes for B and D.