Suppose that 18.84 mL of 0.315 M Ca(OH)2
is required to neutralize 18.2 mL of aqueous HCl solution. What is the molarity of the HCl solution?
All help is appreciated. Would also like help showing which numbers go where within any equations!
Thanks so much!
Why can't you do this? It's just like the last problem. After you see a problem worked you should be able to use that as a template and work similar problems.
To find the molarity of the HCl solution, we can use the following equation:
M1V1 = M2V2
where M1 and V1 are the molarity and volume of the Ca(OH)2 solution, and M2 and V2 are the molarity and volume of the HCl solution.
Given:
M1 = 0.315 M (molarity of Ca(OH)2)
V1 = 18.84 mL (volume of Ca(OH)2)
V2 = 18.2 mL (volume of HCl)
Let's plug these values into the equation:
(0.315 M)(18.84 mL) = M2(18.2 mL)
Now, let's solve for M2, the molarity of the HCl solution:
M2 = (0.315 M)(18.84 mL) / (18.2 mL)
M2 = 5.9316 / 18.2
M2 ≈ 0.325 M
Therefore, the molarity of the HCl solution is approximately 0.325 M.
To determine the molarity of the HCl solution, we can use the concept of stoichiometry and the balanced chemical equation for the reaction between Ca(OH)2 and HCl.
The balanced chemical equation for the reaction is:
Ca(OH)2 + 2HCl -> CaCl2 + 2H2O
Here, we can see that 1 mole of Ca(OH)2 reacts with 2 moles of HCl.
First, we need to calculate the number of moles of Ca(OH)2 using the given volume and molarity:
moles of Ca(OH)2 = volume (in L) × molarity
= 18.84 mL × (1 L / 1000 mL) × 0.315 M
= 0.0059384 moles
Since the stoichiometric ratio between Ca(OH)2 and HCl is 1:2, we can conclude that 0.0059384 moles of Ca(OH)2 will react with twice as many moles of HCl.
Given that the volume of the HCl solution is 18.2 mL, we can calculate the number of moles of HCl:
moles of HCl = (0.0059384 moles Ca(OH)2) × (2 moles HCl / 1 mole Ca(OH)2)
= 0.0118768 moles
Finally, to calculate the molarity of the HCl solution, we divide the moles of HCl by the volume in liters:
molarity of HCl = moles of HCl / volume (in L)
= 0.0118768 moles / (18.2 mL × (1 L / 1000 mL))
≈ 0.652 M
Therefore, the molarity of the HCl solution is approximately 0.652 M.